Error updating database php mysql

13-Nov-2019 14:37

Since the parameters are equal, a further reference to the previous link is returned.So also changes the second mysql_select_db the selected DB of $conn to 'db2'. mysql_error()); This will print out something like... Query: SELECT * FROM table Error: (err_no) Bla bla bla, you did everything wrong It's very useful to see your query in order to detect problems with syntax.You have an error in your SQL syntax; check the manual that corresponds to your My SQL server version for the right syntax to use near '' at line 1 The query seems not to be producing a result. i have commented out some lines which i thought where a problem but they are fine. though I'd be looking at something a little more robust in production code.I am passing an id to a function via a url but the variable seems to die although it seems to be in scope. Still, that should be enough to identify the immediate problem.As far as I can tell the two escape functions don't escape the same characters, which is why you need both (the first for SQL and the second for HTML/JS).

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i am getting an error as below Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\test\on line 232 Error.

The problem with this is that valid values for $res are: a mysqli_result object , true or false This doesn't tell us that there has been an error with the sql used.

If you pass an update statement, false is a valid result if the update fails.

You may also want to actually output the query before trying to execute it in case, for example, there's a problem with The message you are receiving is saying that the result of that query is a true/false, not a mysql "resource".

My SQL resources are the normal response of a mysql query, and they can be "read" by using mysql_fetch_array or mysql_fetch_assoc, etc.

i am getting an error as below Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\test\on line 232 Error.

The problem with this is that valid values for $res are: a mysqli_result object , true or false This doesn't tell us that there has been an error with the sql used.

If you pass an update statement, false is a valid result if the update fails.

You may also want to actually output the query before trying to execute it in case, for example, there's a problem with The message you are receiving is saying that the result of that query is a true/false, not a mysql "resource".

My SQL resources are the normal response of a mysql query, and they can be "read" by using mysql_fetch_array or mysql_fetch_assoc, etc.

The following code returns two times the same error, even though I would have expected only one: $ conn = mysql_connect ('localhost', 'root', ''); $ conn2 = mysql_connect ('localhost', 'root', ''); mysql_select_db ('db1', $ conn); mysql_select_db ('db2', $ conn2); $ result = mysql_query ("select 1 from dual", $ conn); $ result2 = mysql_query ("select 1 from luad", $ conn2); echo mysql_error ($ conn) "".